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Str $

Walter

have the following seltsame Result

declare num&,strg$,b&

strg$="1.3"
num& = val(strg$)

print st$(num&) ' Result 1
print st$(val(strg$)) ' Result 1.3
waitinput

can me Please someone help, the To understand?

freeprofan Interpreter 0.9.5.12

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« this Posting watts as Solution marked. »

Jörg
Sellmeyer

Solution

this is no moreover verwunderliches Result. I Have now no FreeProfan active but the ought to alike his:

print st$(num&) ' Result 1
In num& go no Nachkommstellen stored, therefore can there only 1 rauskommen, if You The Variable anew ausliest.

If you num! take, sustain You the desired result.

XProfan X3
Windows XP SP2 XProfan X4
... und hier mal was ganz anderes als Profan ...

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Walter

sometimes is one even vernagelt!
cordial Thanks!

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