XProfan

English

Imho becomes this View source:

cls
print $profVer
var x&=$FFFFFFFE
casenot x&=$FFFFFFFE : messageBox "Fehler","",0
waitInput
end

not correctly worn out:

Hierbei set I x& on the worth $FFFFFFFE and question thereafter x& ex whether it whom same worth $FFFFFFFE own. becomes but "nein" determined.

or übersehe I thereby something?

so GEHTS:

Compile Mark Separation

cls
print $profVer
var x&=-2
casenot x&=-2 : messageBox "Fehler","",0
waitInput
end

so not:

Compile Mark Separation

cls
print $profVer
var x&=-2
casenot x&=$FFFFFFFE : messageBox "Fehler","",0
waitInput
end

and so GEHTS too:

Compile Mark Separation

cls
print $profVer
var x&=$FFFFFFFE
casenot x&=-2 : messageBox "Fehler","",0
waitInput
end

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02/10/11 ▲

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- Page 2 -

RGH

$FFFFFFE is of itself from now time one positiver worth. too Hexwerte can with a omen slip go, -2 would in Hex now time -$2.

nevertheless can the worth one Longint without Overflow-Message allocated go. even yet more values. (the was sure a bewußte decision, there too a Error Message possible been would.)

then go simply The niedrigsten 4 byte (=32 bit) the Wertes. there but with one Signed-Longint (as well as with one Signed-Quad) the supreme bit for the omen standing, goes the Wertebereich even only To $7FFFFFFF. values ex $80000000 then as negative interprets (Überlauf).

Greeting
Roland

Intel Duo E8400 3,0 GHz / 4 GB RAM / 1000 GB HDD - ATI Radeon HD 4770 512 MB - Windows 7 Home Premium 32Bit - XProfan X4

02/10/11 ▲

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this is me so already clear.

a& as signedLong has whom Wertebereich of -2147483648 To +2147483647 -

if a& means the value -2 carry, then stand The Bytes on FE FF FF FF just as as Bytes with $FFFFFFFE on FE FF FF FF stand.

I have Yes same understood, that the XProfan in this drop the $FFFFFFFE even differently "interpretiert" and the it for a Statement (omen) gives.

I find however somehow neither correctly., that one 32-bit-Long with worth -2 not the Bytefolge $FFFFFFFE coincide but should can it naturally to accept there by the $/Hex-characters nunmal then in XProfan not 1:1 The Bytes meant his must separate even a "Interpretation".

02/10/11 ▲

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to-zei-chen-bit...

02/10/11 ▲

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Frabbing (10.02.11)

to-zei-chen-bit...

Ah, you mean to-zei-chen-bit, not about Vorzei-chenbit or quite V-orzeiche-nbit or. vo-rze-I-enb-it - No, its the to-zei-chen-bit.

the missing still but not $FFFFFFFE - means is still clear with the bit the it itself ums Vorzeichenbit deals if with 32-bit-Long compared becomes.

somehow be I well To stumpf... ^^

02/10/11 ▲

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where is because the Vorzeichenbit?

02/10/11 ▲

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RGH

the Vorzeichenbit is the höchstwertige bit, means jenes, the with $80000000 staid becomes, if it itself for a vorzeichenloses Longint deals.

Greeting
Roland

Intel Duo E8400 3,0 GHz / 4 GB RAM / 1000 GB HDD - ATI Radeon HD 4770 512 MB - Windows 7 Home Premium 32Bit - XProfan X4

02/10/11 ▲

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old Spielverderber.

02/10/11 ▲

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@Frank: to-zei-chen-bit...

02/10/11 ▲

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Frabbing (10.02.11)

very, then schreib time -2 as 32 and as 64 bit-number binary among themselves and you should your mistake discern...

Schreib time $FFFFFFFE and -2 each 32-Bittig among themselves and the power of Grayskull is mitdir...

02/10/11 ▲

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Schreib time $FFFFFFFE and -2 each 32-Bittig among themselves

is Yes no challenge.

there's the puzzel the whole disappeared Postings today already rätselhafter...

02/10/11 ▲

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RGH

The following Program shows (ex the next Delivery the Subscriptionsversion)* The Zusammenhänge:

Compile Mark Separation

proc bits

    declare string erg

    if ptype$(1)="&"

        parameters long worth

        whileloop 31, 0, -1

            erg = erg + st$(testbit(worth, &loop))

        endwhile

    elseif ptype$(1)="Q"

        parameters quad worth

        whileloop 63, 0, -1

            erg = erg + st$(testbit(worth, &loop))

        endwhile

    endif

    return erg

endproc

declare long l, quad q, long hi, lo
l = $7FFFFFFF
q = $7FFFFFFF
print l;tab(46);bits(l)
print q;tab(14);bits(q)
l = $80000000
q = $80000000
print l;tab(46);bits(l)
print q;tab(14);bits(q)
l = $A0000000
q = $A0000000
print l;tab(46);bits(l)
print q;tab(14);bits(q)
l = $A0000000 * 4
q = $A0000000 * 4
print l;tab(46);bits(l)
print q;tab(14);bits(q)
l = -$FFFFFFFE
q = -$FFFFFFFE
print l;tab(46);bits(l)
print q;tab(14);bits(q)
waitinput

* currently there another couple Problems with QuadInts, as they as Parameter on Procedures transfer and be moreover needed Delphi yet something Nachhilfe, so The binären Operators too with Int64 (=Quad) functions, what moreover led that |, &, <<, >>, TestBit() and SetBit() only To 32 bit correctly funktionierten.

Greeting
Roland

Intel Duo E8400 3,0 GHz / 4 GB RAM / 1000 GB HDD - ATI Radeon HD 4770 512 MB - Windows 7 Home Premium 32Bit - XProfan X4

02/11/11 ▲

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task: "Setzen tappt im dunkeln on possible coole Nature and point with XProfan the 2. bit the Wertes of/ one 32-bit-Long-Variable!"

Solution:

Compile Mark Separation