| |
| |
|
Muemmelmann | Hi,
over two years went everything well, nu need I again Help, I Kriegs not there whether well it pipieinfach is :
have one date in the form "24.12.2016"And the Today date in same shape and would like gladly spend, How many days between this both Meet lying...
many Thanks once more and not laugh!!!
Greeting
Uwe |
|
| |
| |
| |
|
|
Muemmelmann | so, Forum has already helped, now have I it, was Yes simply 
Set("ErrorLevel", 0)
declare date1$,date2$,Diff%
'Eingelesene values zB
date1$=20161001
date2$=20161030
'+----------------------------------------------
Proc DeltaTage_DB_Format
'+----------------------------------------------
'Berechnet amount of Meet between 2 Datumswerten
'Parameter: beginning, end in Datenbankformat
'Rückgabe difference days Integer
Parameters From$,To$
Return dt("DaysBetween", dt("setdate",DToC$(From$)), dt("setdate",DToC$(To$)))
endproc'DeltaTage_DB_Format
' Hauptprogramm
Diff% = DeltaTage_DB_Format(date1$,date2$)
messagebox(st$(diff%),"Differenz-Tage",0) |
|
| |
| |
| |
|
(539)
Deutsch
English
Français
Español
Italia