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usage of oglOrtho

 
- Page 1 -



Andreas
Koch
Hello together,

can someone explain, as korrekte usage of oglOrtho sounds?
I have now already different versions ausprobiert and come not further.
How must I the following example adjust, so I instead of Quadern Rechtecke displayed get?
CompileMarkSeparation
Window 0,0 - 500,500
 $H opengl.ph
oGL("Init", %hwnd, 1, 1, 1, 1)
Ogl("clear")
oGL("Origin", 0, 0, -8)
oGL("Cuboid", 1, 1, 1)
oGL("Origin", -2, 0, -8)
oGL("Cuboid", 1, 1, 1)
oGL("Origin", 2, 0, -8)
oGL("Cuboid", 1, 1, 1)
Ogl("Show")
waitinput
Ogl("clear")
Ogl("glMatrixMode",~gl_projection)
Ogl("glLoadIdentity")
Ogl("glViewport",0,0,Width(%hwnd), Height(%hwnd))
Ogl("glOrtho", 0, 500, 0, 500, -10, 10)
oGL("Origin", 0, 0, -8)
oGL("Cuboid", 1, 1, 1)
oGL("Origin", -2, 0, -8)
oGL("Cuboid", 1, 1, 1)
oGL("Origin", 2, 0, -8)
oGL("Cuboid", 1, 1, 1)
Ogl("Show")
WaitInput
 
11/13/12  
 



 
- Page 2 -


well so How I the at o.g. SpaceShip made have -

have here a "TGA2TEX" vorgemacht: [...]  and a "bmpbmp2tex".
 
11/17/12  
 




funkheld
Hello, where find I these Spacechip.tga and these Stencil ?

Thank you.

greeting
peter
 
11/17/12  
 



in the already named Thread ( [...]  ) have I 2 functions

posted with them You either a TGA or from 2 BMP Files

a TEX File produce can and a TEX-Loaderfunktion is too in the

oglhelper.inc include - means everything what need. an TGA-File create

(had but not there 2 BMPs well plainer To produce are) can You with

different Grafikprogrammen How IrfanView or Gimp. One BMP is simply

the RGB-Image and the 2. BMP can You as Stencil use - according to the

How You The function anpasst can You to determine How the Stencil wirken should

or. whether transparent or semitransparent etc. simply circa a RGBA-Tex-

File To produce.
 
11/18/12  
 




funkheld
I have now 2 BMP-Images made. The go too to a Tex gewandelt.
The shadow is To see. but which colour must as see through colour chosen go for the Hauptobject ? at this time can I nirgends where durchschauen .

How can I only one Hauptbild produce of BMP-Image without these shadow (Stencil) with the Umwandelprogramm ?

Thank you.

greeting
peter
 
11/18/12  
 



The Bytewert the Variable a places whom Alpha-transparency-worth or. The

Durchsichtigkeit the angegebenen colour solid - You can so play and in the code

self determine whom worth a with which colour holds or whether/ when a 0 or 255

or a worth between has.
 
11/18/12  
 




funkheld
this is Yes Mist, the one there no solid colour as Duchsichtigkeit determine can,

I have zero drin in the Image , but appear Black.

greeting
peter

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11/18/12  
 



what write You there? the standing with regard to content Yes very in the Widerspruch to the what

I in previous Posting wrote. You can a still on 0..255 settle as you

popular, z.B. with of/ one designed colour or or...
 
11/18/12  
 




funkheld
How can the image on the Farbwert : FF00FF transparent go.
The others visible colours are then of Farbwert : FF00FF abweichend.

greeting
peter
 
11/18/12  
 



in the code is a:=getrvalue(getPixel(x+xx+1,y)) vorgemacht, means that the

Durchsichtigkeitsgrad itself on the Rotanteil the Pixels orientiert. Mach still

instead something like How a=if(c==$FF00FF,0,255) or. a=c==$FF00FF*255
 
11/18/12  
 



Gib time everything in a Zipdatei then schausch what there verwürgt is.
 
11/19/12  
 




funkheld
this is clarified.
the Schattenbild have I Black made . therefore were any both Images transparent (disappeared).

How do I get the normal Image with whom black to put now transparent ?

Thank you.

greeting

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11/19/12  
 



I faith You want this here:

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to that understanding: You benötigst for this object no of actual Pixelmaterial

abweichendes Stencil-Image there You Yes simply The in the Image located colour 0 with the

Alphawert 0 into TEX take off want. the abweichende Stencil-Image needed

one Yes only then if one additional not Spritebild located Information

for Stencil needed. I have you means a TEXMaker for the Sprite and a

for shadow prepares and for whom OGL-code something minimizes.

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11/19/12  
 




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H.Brill10/29/23
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