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GUI grid / prozentuale distribution of boxes

 

Erasmus.Herold
Hallöchen ...

I have one Grid prepares from 2 Split and 3 Lines
(grid = gui.grid gui.hwnd [2,3])

The upper and the downstairs row should 10% the Displays in claim take, The mittlere row 80 %

weder: gui.height [grid] 10,80,10
yet: gui.height[grid 10,80,10]
find ihren lane.
who can with the right Syntax help, from the Help watts I unfortunately not schlau.

Greeting
Erasmus
 
04/02/16  
 



have You time:
ui.maingrid=gui.grid gui.hwnd [2 [10 80 10]]

probiert? one can namely The sizes too same with as an array indicate. thereafter to control boxes visible make:
gui.theme ui.maingrid -1// gui.theme.debug

otherwise ought to:

the same do. if not, then liegts on yet so many bow in the Module GUI -

so should But functions.
 
04/02/16  
 




Erasmus.Herold
functions and gefällt. thanks. Closed.

 
04/02/16  
 




Michael
W.
with so much Help would I but gladly know, How  it because now functions has.
 
XProfan X3
System: Windows 8/10, XProfan X4
Programmieren, das spannendste Detektivspiel der Welt.
04/03/16  
 




Micha12334
Yes, this is my opinion, especially since IF 2 Opportunities aufzeigte.
 
04/04/16  
 




Erasmus.Herold
so have I the resolved:
// GRID / Matrix
grid = gui.grid gui.hwnd [1,3]
grid_oben = gui.grid([grid,1,1],[1,1])//created one 1x1 Grid in cell 1,1
grid_mitte = gui.grid([grid,1,2],[3,3])//created one 3x3 Grid in cell 1,3
grid_unten = gui.grid([grid,1,3],[1,1])//created one 1x1 Grid in cell 1,3
// distribution the boxes (prozentual)
gui.height grid [10 80 10]
 
04/08/16  
 



here the hint, instead of grid_oben, grid_mitte, simply:

grid.main=
grid.oben=gui.grid [grid.main 1 1] [1 1]
grid.mitte=...

so have Programmweit everything in 1 Variable "grid" stored.
 
04/08/16  
 




Erasmus.Herold
Yes - the power utterly sense and the Programmiererleben slight.
(thumb high)
 
04/08/16  
 



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