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Schwierige Matheaufgabe - Ohmsches law

 

Julian
Schmidt
can me time someone with this task help. I get The really not there.
two in a Kochherd installed Heizwiderstände give in row- 133W and parallelgeschaltet 600W av. which Leistungen go submitted, if eachone Widerständ particular eingeschaltet is.


what we with the task know is, that The Gesamtleistung in the Parallelschaltung 600W totals. and in the Reihenschaltung 133W.
and the the Gesamtwiderstand in the Rows and Parallelschaltung same are.

it counts means first.



Also white to the the thrill in the Reihenschaltung proportional on The Widerstände aufteilt. and the power in the Parallelschaltung antiproportional to the Widerständen. it counts means.



or.



Also besagt the Ohmische law the the power in the Reihenschaltung same big remaining. likewise The thrill in the Parallelschaltung.
Ergo must one so bring into action.



for the Einzelleistungen counts.



How can itself now of these whole Information The Solution(en) to determine?

[OFFTOPIC]hope here gibt’s too a couple good Mathematiker[/OFFTOPIC]

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Julian
Schmidt
has none time drüber geschaut?
 
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05/11/13  
 



my Hirn is for something like To small,

once I Kochherd read krich I hunger!
 
05/11/13  
 




Jörg
Sellmeyer
contact you still time directly on p.woodpecker. The is still the Formelkönig and shake something like certainly from the Ärmel.
 
Windows XP SP2 XProfan X4
... und hier mal was ganz anderes als Profan ...
05/11/13  
 




Ernst
Julian Schmidt (09.05.13)
and the the Gesamtwiderstand in the Rows and Parallelschaltung same are.


has itself in the indicated not one Error eingeschlichen ?
The Gesamtwiderstand can still unmöglich same his, there with the Reihenschaltung the Gesamtwiderstand R=R1+R2 is and with the Parallelschaltung R=(R1*R2)/(R1+R2). If one now a resistance grenzwertig against infinite think, is with the Serienschaltung the Gesamtwiderstand infinite, against it with the Parallelschaltung roughly the worth the smaller Widerstandes. on the other hand the a Widerstandswert with 0 adopted, is in the Serienschaltung the Gesamtwiderstand the worth the second Widerstandes, with the Parallelschaltung but 0 (Kurzschluß).
 
05/11/13  
 




Julian
Schmidt
Jup, haste right.

R 0 = R R1 + R R2



R 0 = ( R P1 -1 + R P2 -1 ) -1



Haste ne idea How I The task heran weg can?

[OFFTOPIC]hope MathML becomes of all large Browsern supported.[/OFFTOPIC]
 
XProfan X2
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05/11/13  
 



[offtopic]
hint: gives too [ math ].

x = b ± b 2 4 a c 2 a


[/offtopic]
 
05/11/13  
 




Julian
Schmidt
[OFFTOPIC]UI, yummy

Chrome and IE can the unfortunately not correctly. present [/OFFTOPIC]
 
XProfan X2
Win7 Professional, SP1, AMD FX(tm)-8350 Eight-Core Processor

˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗
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Julian
Schmidt
[OFFTOPIC]green works somehow freundlicher
Padding reicht 10-15px.
[/OFFTOPIC]





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XProfan X2
Win7 Professional, SP1, AMD FX(tm)-8350 Eight-Core Processor

˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗˗
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05/12/13  
 



[OFFTOPIC]find? Have now time green tuned.[/OFFTOPIC]
 
05/12/13  
 




E.T.
iF (12.05.13)
find? Have now time green tuned.


but withal green  goes The Formel in a Kurzschluss
ever which indicated voices there well not...
 
Grüße aus Sachsen... Mario
WinXP, Win7 (64 Bit),Win8(.1),Win10, Win 11, Profan 6 - X4, XPSE, und 'nen schwarzes, blinkendes Dingens, wo ich das alles reinschütte...
05/12/13  
 




Julian
Schmidt
It can too his not R 0 , separate R 1 and R 2 in Reihenschaltung and Parallelschaltung whom equal worth having.

R R0 = R 1 + R 2



R P0 = ( R 1 -1 + R 2 -1 ) -1

 
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05/12/13  
 




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